Physics, asked by garimamohindhru3084, 10 months ago

A voltmeter has a resistance of 120 ohms. When it is connected to battery of EMF 9 volts and internal resistance 15 ohms, then the reading of voltmeter is

Answers

Answered by skyfall63
1

The reading of the voltmeter is 8V.

Explanation:

The voltage divider concept is used to solve circuits in order to simplify the solution. Applying this law would also thoroughly solve simple circuits. The main concept of this voltage divider theory is 'the voltage is divided between two resistors that are directly connected in proportion to their series resistance.'

Given: Voltmeter resistance = 120 Ω

Battery EMF = 9 volts.

Internal resistance, R = 15Ω

Current, I = \frac{V}{R}

=  \frac{9}{15+120}\frac{9}{135} ⇒0.066 Amp.

So, voltage drop = 0.0667 x 15 = 1V

Therefore, Voltmeter reading = 9 - 1 = 8 V

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