Question

a voltmeter has resistance 30 ohm what will be its reading when it is connected across a cell of EMF 2 V having internal resistance 10 ohm​

Answer 1

Answer:

1.5 V.

Explanation:

I = E / R+r

I = E / R+r I = 2/ 30 + 10

I = E / R+r I = 2/ 30 + 10 I = 2 / 40

I = E / R+r I = 2/ 30 + 10 I = 2 / 40 I = 1/20 Amperes

I = E / R+r I = 2/ 30 + 10 I = 2 / 40 I = 1/20 Amperes V = E - Ir

I = E / R+r I = 2/ 30 + 10 I = 2 / 40 I = 1/20 Amperes V = E - Ir V = 2 - (1/20 × 10)

I = E / R+r I = 2/ 30 + 10 I = 2 / 40 I = 1/20 Amperes V = E - Ir V = 2 - (1/20 × 10) V = 2 - 1/2

I = E / R+r I = 2/ 30 + 10 I = 2 / 40 I = 1/20 Amperes V = E - Ir V = 2 - (1/20 × 10) V = 2 - 1/2 V = 3/2

I = E / R+r I = 2/ 30 + 10 I = 2 / 40 I = 1/20 Amperes V = E - Ir V = 2 - (1/20 × 10) V = 2 - 1/2 V = 3/2 V = 1.5

Hope it helps

Answer 2

Answer:

15 ohm is i think write answer and take this answer yes ya no as you wish....