Question

A volume occupied by 4.4g of CO2 at STP is

Answer 1

Answer:

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Explanation:

Ans. No. of moles of CO2 present=given mass /molar mass

=> 4.4/44 = 0.1 moles

No. of moles = given vol. / 22.4 litres

=> 0.1= given vol./22.4 litres

=> 0.1*22.4 = given vol.

Given vol is the required vol. here,

So the vol. occupied by 4.4g of CO2 is 2.24 liters.

Answer 2

Answer:

1 mol of a gas occupies 24dm^3 at RTP

1 mol of CO2 has a molecular mass of 44g (12+16*2)

moles of CO2=4.4/44 = 0.1mol

volume=0.1mol*24dm^3 = 2.4dm^3

or = 2.4*1000 cm^3, i.e. 2400cm^3

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