Question

A volume occupied by 4.4g of CO2 at STP is

(a) 22.4L
(b) 2.24L
(c) 0.224L
(d) 0.1 L

Answer 1

halo dude , your answer is --

firstly we find the molar mass of CO2 ,
CO2 = 12 + 16×2 = 12 + 32 = 44 g

now, 1 mole of CO2 = 44g ...(1)
also, volume of 1 mole of CO2 = 22.4L ( at STP) ....(2)

from (1) & (2)

44g = 22.4 L

=> 1g = 22.4/44

so, 4.4 g = 22.4 ×4.4/44 = 2.24L

hence, a volume occupied by 4.4 g of CO2 at STP is 2.24L

option (b) is right

hope it help you

Answer 2

Option (b) 2.24L

A volume occupied by 4.4g of CO2 at STP is  2.24L

Explanation:

Given gas is $CO2$

Here we will find the molar mass of  $CO2$

$CO2 = 12 + 16$×$2 = 12 + 32 = 44 g$

now,we will find that 1 mole of CO2 will have a molar mass = 44g ...(1)

also, We know that volume of 1 mole of CO2 at STP is= 22.4L ....(2)

from equation (1) & (2)when we equate both the equation we get

$44g = 22.4 L$

$= > 1g = 22.4/44$

so, $4.4 g = 22.4$×$4.4/44 = 2.24L$

hence, a volume occupied by $4.4 g$ of CO2 at STP is $2.24L$

option (b) is right

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