Question

A volume of 10 ml of gasses C4Hx exactly requires 55ml O2 for complete combustion,the value of x is​

Answer 1

Answer:

X=6

Explanation: C4Hx + (4+x/4)O2 = 4Co2 + X/2H2O

1ml of C4Hx = (x/4 + 4) ml of O2

10ml of C4Hx = (x/4+4)*10 ml of O2

So,

(X/4+4)*10=55

X/4*10 + 4*10 = 55

10x + 160 =120

X=6 Ans.

Thank you and have a nice day.

Answer 2

Given: A volume of 10 ml of gasses C4Hx exactly requires 55ml O2 for complete combustion.

To find: We have to find the value of x.

Solution:

To determine the value of x we have to follow the below steps-

The combustion equation of $C_4H_x$ and oxygen is given as follows-

$C_4H_x+(4+x/4)O_2\rightarrow 4CO_2+x/2H_2O$

Thus we can write,

1 ml of $C_4H_x$ requires $(4+x/4)$ ml oxygen gas.

Thus 10 ml of $C_4H_x$ requires $10(4+x/4)$ ml oxygen gas.

Given that for complete combustion the amount of oxygen required is 55 ml.

So, we can write-

$10(4 + \frac{x}{4} ) = 55 \\2(4 + \frac{x}{4} ) = 11 \\ 8 + \frac{x}{2} = 11 \\ \frac{x}{2} = 3 \\ x = 6$

The value of x is 6.