Question

A voluntary flask containing 50% (w/w) solution how many grams of given sulphuric acid solution is required to prepare 200 ml of 0.5M and H2SO4 solution?
A]75gm
B]85gm
C]9.8gm
D]15gm​

Answer 1

Dear Student,

● Answer -

(C) 9.8 gm

◆ Explanation -

Molarity of the solution is calculated by -

Molarity = moles of solute / volume of solution

Molality = (given mass / molar mass) / volume of solution

Given mass = molarity × molar mass × volume of solution

Given mass = 0.5 × 98 × 0.2

Given mass = 9.8 g

Therefore, 9.8 g of H2SO4 solution is required.

Thanks dear. Hope this helps you...