CBSE BOARD XII, asked by bvandana031, 9 months ago

A walks 30m towards east direction and turns to the north and walk 40m. How far is he from his original position​

Answers

Answered by nithrashing3
1

Explanation:

the Pythagoras theorem will be applying in this take 30 m as the base 40 m as perpendicular so ans will be

√30*30+40*40

√900+1600

√2500

√5*5*5*5*2*2

5*5*2

=50 m ans

Answered by arvindlaks2005
0

Answer:

nnh

Explanation:

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