A walks around a circular field at the rate of one round per hour while b runs around it at the rate of six rounds per hour. they start at same point at 7:30 am. they shall first cross each other at ?
Answers
Relative speed between two = 6-1 = 5 round per hour
They will cross when one round will complete with relative speed,
which is 1/5 hour = 12 mins.
So 7:30 + 12 mins = 7:42
They will cross first at 7:42 AM
Step-by-step explanation:
A walks around a circular field at the rate of one round per hour
while b runs around it at the rate of six rounds per hour
Let say Circular Field perimeter = D
A coveres D in 1 hrs
B coveres 6D in 1 Hrs
first Time when they cross Each other
A covers = y then B Covers = D + y
Time Taken to cover y by A = y/D hrs
Time taken to cover D + y by B = (D + y)/6D
y/D = (D + y)/6D
=> 6y = D + y
=> y = D/5
Time Taken to cover y by A = y/D = 1/5 hrs = 12 mins
They will cross first at 7:30 + 0:12 = 7:42 AM
Learn more:
)vinay runs 100 metres in 20 seconds and ajay runs the same ...
https://brainly.in/question/9420558