Question

A wall 20 m long. 4m high and 72 mm thick, is to be constructed using bricks of dimensions. 32* 18*10 . How many bricks will be required.?​

Answer 1

$\large \color{aqua}\: { \underline{Dimensions \: of \: the \: wall \: :- \: }}$

$\color{lime} { \underline{Length \: of \: the \: wall \: = \: 2 \times 100 = 200cm}}$

$\color{gold}{ \underline{Height \: of \: the \: wall \: = \: 4 \times 100 = 400cm}}$

$\color{silver} { \underline{Breadth \: of \: the \: wall \: = \: \frac{72}{10} = 7.2cm}}$

$\color{aqua} { \underline{Dimensions \: of \: the \:bricks \: :-}}$

$\color{lime} { \underline{32cm \times 18cm \times 10cm}}$

$\large \color{skyblue} { \underline{Now \: lets \: solve \: :-}}$

$Volume \: of \: the \: wall \: = \: 200 \times 400 \times 7.2 = 576000cm³$

$Volume \: of \: 1 \: brick \: = \: 32 \times 18 \times 10 = {5760cm}^{3}$

$Number \: of \: bricks \: required \: to \: construc t\: the \: wall \: = \: \\ \\ \frac{volume \: of \: the \: wall}{volume \: of \: 1 \: brick}$

$Number \: of \: bricks \: required \: to \: construc t\: the \: wall \: = \: \\ \\ \frac{576000}{5760}$

$Number \: of \: bricks \: required \: = \: 100$

$\large \color{red}{ \underline{ \therefore \: Number \: of \: bricks \: required \: to \: construct \: the \: wall \: = \: 100}}$