A wall 24m long ,5 m high and 0.25m thick is to be constructed using bricks measuring 25cm×12.5cm×7.5cm. Find the no. of bricks required,if 5% of the wall is occupied by cement and sand mixture.
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Volume of the wall = 2400*500*25= 30000000 cm³
Volume of brick= 25*12.5*7.5=2343.75
Volume to be covered by sand & cement is 5%
Hence volume covered by brick =(100-5)%=95%
Volume of wall to be covered by brick= 30000000*95/100= 28500000
No. of brick required=28500000/2343.75= 12160
No. of brick used are 12160
Volume of brick= 25*12.5*7.5=2343.75
Volume to be covered by sand & cement is 5%
Hence volume covered by brick =(100-5)%=95%
Volume of wall to be covered by brick= 30000000*95/100= 28500000
No. of brick required=28500000/2343.75= 12160
No. of brick used are 12160
mathbubble8:
Thanks again. But in the statement volume of wall to be covered by bricks why did we multiplied 30000000*95? From where 95 came?
please mark as the best...........
Sure !
But why did we minus (hundered-5)% ??
100 % wall is made of 5% cement and rest by bricks
Okay.
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