Math, asked by aiket, 9 months ago

A wall 4.8m long and 3.5m high is covered with rectangular tiles of size 12cm by 10 cm. Find the total cost of the tiles at the rate of ₹2.50 per tile. Q3

Answers

Answered by Anonymous
116

AnswEr :

\bold{Wall \:Dimension} \begin{cases}\sf{Length(L)=4.8m= 480 cm} \\ \sf{Breadth(B)=3.5m = 350 cm}\end{cases}

\bold{Tiles \:Dimension} \begin{cases}\sf{Length(l)=12cm} \\ \sf{Breadth(b)=10cm}\end{cases}

Let's Head to the Question Now :

\longrightarrow \tt Area \:of \: Wall = Area \:of \:Tiles \times Number \\  \\ \longrightarrow \tt L \times B = l \times b \times Number \\  \\ \longrightarrow \tt480 \times 350 = 12 \times 10 \times Number \\  \\ \longrightarrow \tt \dfrac{ \cancel{480} \times 350}{\cancel{120}} = Number \\  \\ \longrightarrow \tt4 \times 350 = Number  \\  \\ \longrightarrow \orange{\tt Number = 1400}

\rule{300}{2}

T O T A L C O S T :

\implies \tt Cost = Number\:of\:Tiles  \times Rate\\ \\ \implies \tt Cost = 1400 \times 2.5 \\ \\ \implies \tt Cost = 14\cancel{00}\times \dfrac{25}{ \cancel{100}} \\ \\ \implies \tt Cost = 14 \times 25 \\ \\ \implies \large \boxed{ \red{\tt Cost = Rs.3500}}

Therefore, Cost of tiling is Rs. 3500

Answered by Anonymous
50

\bold{\Huge{\underline{\boxed{\sf{\orange{ANSWER\::}}}}}}

\bold{\Large{\underline{\sf{\green{Given\::}}}}}

A wall 4.8m long & 3.5m high is covered with rectangular tiles of size 12cm by 10cm.

\bold{\Large{\underline{\rm{\red{To\:find\::}}}}}

The cost of the tiles at the rate of ₹2.50 per tile.

\bold{\Large{\underline{\sf{\purple{Explanation\::}}}}}

We have,

  • Length of the wall= 4.8m
  • Breadth of the wall= 3.5m

We know that formula of the rectangle: [Length × Breadth]    [sq.units]

  • Area of the wall:

→ 4.8m × 3.5m

→ 16.8m²

If we convert into cm then,

\bold{\large{\boxed{\sf{1m²=10000cm}}}}

Therefore,

→ (16.8× 10000)cm²

→ 168000cm²

&

  • Area of rectangular tiles:

We have,

\bold{\begin{cases}\sf{Length=12cm}\\ \sf{Breadth=10cm}\end{cases}}

→ Area= (12×10)cm²

→ Area= 120cm²

Now,

\bold{Number\:of\:tile=\frac{Area\:of\:wall}{Area\:of\:rectangular\:tiles} }

\bold{Number\:of\:tile=\cancel{\frac{168000cm^{2} }{120cm^{2} }} }

\bold{\boxed{Number\:of\:tile=1400}}}}

  • Total cost of tiles:

The rate of 1 tile= ₹2.50

So,

The rate of 1400 tile= ₹(1400× 2.50)

∴The rate of 1400 tile = ₹3500

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