Question

A wall 4.8m long and 3.5m high is covered with rectangular tiles of size 12cm by 10 cm. Find the total cost of the tiles at the rate of ₹2.50 per tile. Q3

Answer 1

AnswEr :

$\bold{Wall \:Dimension} \begin{cases}\sf{Length(L)=4.8m= 480 cm} \\ \sf{Breadth(B)=3.5m = 350 cm}\end{cases}$

$\bold{Tiles \:Dimension} \begin{cases}\sf{Length(l)=12cm} \\ \sf{Breadth(b)=10cm}\end{cases}$

• Let's Head to the Question Now :

$\longrightarrow \tt Area \:of \: Wall = Area \:of \:Tiles \times Number \\ \\ \longrightarrow \tt L \times B = l \times b \times Number \\ \\ \longrightarrow \tt480 \times 350 = 12 \times 10 \times Number \\ \\ \longrightarrow \tt \dfrac{ \cancel{480} \times 350}{\cancel{120}} = Number \\ \\ \longrightarrow \tt4 \times 350 = Number \\ \\ \longrightarrow \orange{\tt Number = 1400}$

$\rule{300}{2}$

• T O T A L ⠀C O S T :

$\implies \tt Cost = Number\:of\:Tiles \times Rate\\ \\ \implies \tt Cost = 1400 \times 2.5 \\ \\ \implies \tt Cost = 14\cancel{00}\times \dfrac{25}{ \cancel{100}} \\ \\ \implies \tt Cost = 14 \times 25 \\ \\ \implies \large \boxed{ \red{\tt Cost = Rs.3500}}$

⠀

∴ Therefore, Cost of tiling is Rs. 3500

Answer 2

$\bold{\Huge{\underline{\boxed{\sf{\orange{ANSWER\::}}}}}}$

$\bold{\Large{\underline{\sf{\green{Given\::}}}}}$

A wall 4.8m long & 3.5m high is covered with rectangular tiles of size 12cm by 10cm.

$\bold{\Large{\underline{\rm{\red{To\:find\::}}}}}$

The cost of the tiles at the rate of ₹2.50 per tile.

$\bold{\Large{\underline{\sf{\purple{Explanation\::}}}}}$

We have,

• Length of the wall= 4.8m
• Breadth of the wall= 3.5m

We know that formula of the rectangle: [Length × Breadth]    [sq.units]

• Area of the wall:

→ 4.8m × 3.5m

→ 16.8m²

If we convert into cm then,

$\bold{\large{\boxed{\sf{1m²=10000cm}}}}$

Therefore,

→ (16.8× 10000)cm²

→ 168000cm²

&

• Area of rectangular tiles:

We have,

$\bold{\begin{cases}\sf{Length=12cm}\\ \sf{Breadth=10cm}\end{cases}}$

→ Area= (12×10)cm²

→ Area= 120cm²

Now,

→ $\bold{Number\:of\:tile=\frac{Area\:of\:wall}{Area\:of\:rectangular\:tiles} }$

→ $\bold{Number\:of\:tile=\cancel{\frac{168000cm^{2} }{120cm^{2} }} }$

→ $\bold{\boxed{Number\:of\:tile=1400}}}}$

• Total cost of tiles:

The rate of 1 tile= ₹2.50

So,

The rate of 1400 tile= ₹(1400× 2.50)

∴The rate of 1400 tile = ₹3500