Question

A wall 484 cm long and 310 cm high is covered with rectangular tiles of
size 22 cm by 10 cm. Find the number of tiles required to cover the wall

Answer 1

Answer :-

• The required number of tiles are 682 tiles.

Step-by-step explanation:

To Find :-

• Number of tiles required to cover the wall

Solution:

Given,

• Length of the wall = 484cm
• Breadth of the wall = 310cm

Therefore, the area of the wall is,

=> Length × Breadth

=> 484cm × 310cm

=> ( 484 × 310 ) cm²

=> 150040cm²

Also given,

• Length of a tile = 22cm
• Breadth of a tile = 10cm

Therefore, the area of the tile is

=> Length × Breadth

=> 22cm × 10cm

=> ( 22 × 10 ) cm²

=> 220cm²

According the question,

Number of tiles required:

=> Area of the wall ÷ Area of a tile

=> 150040 ÷ 220

=> 682

Hence,

• The required number of tiles are 682 tiles.

Answer 2

Step-by-step explanation:

★ Concept :-

Here the concept of Area of Rectangle has been used. As we see, that we are given the length and the breadth of the wall and the tiles also. Then firstly we will find out the area of the wall. Then we will find out the area of the tile. After that, by dividing the area of the wall with the area of tile we will find out the number of tiles required to cover the wall.

Let's do it !!!

___________________

★ Formula Used :-

$\star\;\underline{\boxed{\sf{\pink{Area\ of\ Rectangle\ =\ \bf Length \times Breadth.}}}}$

___________________

★ Solution :-

Given,

➼ Length of the wall = 484cm.

➼ Breadth of the wall = 310cm.

Also given,

↬ Length of the tile = 22cm.

↬ Breadth of the tile = 10cm.

---------------------------------------------------------------

~ For the Area of the wall ::

We know that,

$\sf \rightarrow {Area\ of\ the\ wall\ =\ \bf Length \times Breadth}$

⦾ By applying the values, we get :-

$\sf \rightarrow {Area\ of\ the\ wall\ =\ \bf Length \times Breadth}$

$\sf \rightarrow {Area\ of\ the\ wall\ =\ \bf 484cm \times 310cm}$

$\sf \rightarrow {Area\ of\ the\ wall\ =\ \bf (484 \times 310)cm^2}$

$\bf \rightarrow {Area\ of\ the\ wall\ =\ {\red {150040cm^2.}}}$

∴ Hence, area of the wall = 150040cm².

---------------------------------------------------------------

~ For the Area of the tile ::

We know that,

$\sf \mapsto {Area\ of\ the\ tile\ =\ \bf Length \times Breadth}$

⦾ By applying the values, we get :-

$\sf \mapsto {Area\ of\ the\ tile\ =\ \bf Length \times Breadth}$

$\sf \mapsto {Area\ of\ the\ tile\ =\ \bf 22cm \times 10cm}$

$\sf \mapsto {Area\ of\ the\ tile\ =\ \bf (22 \times 10)cm^2}$

$\bf \mapsto {Area\ of\ the\ tile\ =\ {\orange {220cm^2.}}}$

∴ Hence, area of the tile = 220cm².

---------------------------------------------------------------

~ For the Number of tiles required ::

By relationship, we know that,

$\sf : \implies {No.\ of\ tiles\ required\ =\ \bf Area\ of\ the\ wall \div Area\ of\ the\ tile}$

⦾ By applying the values, we get :-

$\sf : \implies {No.\ of\ tiles\ required\ =\ \bf Area\ of\ wall \div Area\ of\ the\ tile}$

$\sf : \implies {No.\ of\ tiles\ required\ =\ \bf 150040 \div 220}$

$\bf : \implies {No.\ of\ tiles\ required\ =\ {\blue {682.}}}$

∴ Hence, no. of tiles required = 682.

___________________

★ More to know :-

$\sf \leadsto {Perimeter\ of\ Rectangle\ =\ 2(l\ +\ b).}$

$\sf \leadsto {Area\ of\ Rectangle\ =\ Length \times Breadth.}$

$\sf \leadsto {Diagonal\ of\ Rectangle\ =\ \sqrt{l^2\ +\ b^2}.}$