Question

A wall 6 m long, 5 m high and 0.5 m thick is to be constructed with bricks, each having length 25 cm, breadth 12.5 cm and height 7.5 cm.

Find the number of bricks required to construct the wall, if it is given that cement and sand mixture occupy $\frac{1}{20}$ of the volume of the wall.

Please provide complete steps and justifications.

Answer 1

Let the dimensions of the wall be
L=6m=600cm
B=5m=500cm
H=0.5m=50cm
1) volume of the wall=V=LBH cu cm
V=600*500*50cc---(1)
2)volume of the wall excluding occupied by cement and other material =19/20*V
=19(600*500*50)/20
=19*(30*500*50)cucm---(2)
Let the number of bricks required for wall=n
n=(2)/each brick volume)
n=(19*30*500*50)/(25*12.5*7.5)
=1520 Number of bricks required =n 1520

Answer 2

Answer:

Let the dimensions of the wall be

L=6m=600cm

B=5m=500cm

H=0.5m=50cm

1) volume of the wall=V=LBH cu cm

V=600*500*50cc---(1)

2)volume of the wall excluding occupied by cement and other material =19/20*V

=19(600*500*50)/20

=19*(30*500*50)cucm---(2)

Let the number of bricks required for wall=n

n=(2)/each brick volume)

n=(19*30*500*50)/(25*12.5*7.5)

=1520 Number of bricks required =n 1520