A wall 6m long 5m hight and 0.5m think is to be constructed with bricks each having length 25cm breath 12.5cm and hight 7.5cm find the number of bricks required to construct the wall if it is given that cannot of the volume of the wall.
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To get the number of bricks,you need to divide the wall Total.Surface.Area by each brick T.S.A
T.S.A of the wall=2(lb+bh+hl)
=2(6*5 + 5*0.5 + 0.5*6)
=2(30 + 2.5 + 3)
=2(35.5)
=71m
T.S.A of each brick=2(lb+bh+hl)
Here,
length=25cm=0.25m
breadth=12.5cm=0.125m
height=7.5cm=0.075m
So by substituting these values,we get
2(0.25*0.125 + 0.125*0.075 + 0.075*0.25
)
=2(0.03125 + 0.009375 + 0.01875)
=2(0.059375)
=0.11875
Hence,
=71/0.11875
=598 bricks (approx)
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