Math, asked by jayantkumarmuz2007, 11 months ago

a wall 7 1/5 m in height is being built after one day the masons had built 7/9 of the wall what height of the wall is yet to be built

Answers

Answered by sawhneyavneeshpdax3q
31

Please Mark It As The BRAINLIEST

Height of wall

= 7 1 = 36

     5       5

Part built by the masons

= 7 of the wall

   9

= 7 X 36

   9       5

= 7 X 4

          5

= 28

    5

Part left

= 36 - 28

    5        5

= 8

   5

In Mixed Fraction

= 1 3

     5

Answered by smithasijotsl
8

Answer:

∴The height of the wall to be built =  1\frac{3}{5}m

Step-by-step explanation:

Given,

The total height of the wall =  7\frac{1}{5}m

The part of the wall built in one day = \frac{7}{9}

To find,

The height of the wall to be built

Solution:

The total height of the wall = 7\frac{1}{5}m = \frac{36}{5}m

Since  \frac{7}{9} part of the wall is built in one day, the height of the wall completed in one day =  \frac{36}{5}× \frac{7}{9}

= \frac{4X7}{5}

= \frac{28}{5}m

The height of the wall completed in one day = \frac{28}{5}m

The height of the wall to be built = Total height of the wall - part of the wall built

= \frac{36}{5} -  \frac{28}{5}

= \frac{8}{5}

= 1\frac{3}{5}m

∴The height of the wall to be built =  1\frac{3}{5}m

#SPJ2

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