Question

a wall 9.68 M long and 6.2 M high is covered with rectangular tiles of size 44 cm by 20cm.find the Total cost of the tiles at the rate of rupees 18.50 per tiles.

Answer 1

For Wall :
L: 9.68m = 968 cm
B: 6.2m = 620 cm
Area Of wall =
$968 \times 620$
that is 600160 cm²
For Tiles :
L=44cm
B= 20 cm
area of tiles :
$44 \times 20$
that's
880 cm²
number of tiles =
$600160 \div 880$
that's 682 tiles
cost of 1 tile = R 18.50
cost of 682 tiles =
$682 \times 18.50|$

Answer 2

we have to find the area of wall = 6.2m*9.68m
= 60.078m^2
then we find the area of tiles = 20*44cm
=880cm^2
we convert the m into cm
then 60.078m^2=60,078
we divide the area of wall / area of tiles
60078/880=68.27045
the rate of tiles =18.50*68.27045
=1263.003325