Question

A wall clock has a 5cm long minute hand. The
average velocity of the tip of the hand reacting
6:00 hour to 18:30 hour is​

Answer 1

Given :

The length of min hand = l = 5 cm

The time taken to tip reacting is 6 : 00 hour to 18 : 30 hour

To Find :

The average velocity of the tip

Solution :

Let The average velocity of the tip = v m/sec

∵ length of min hand = 5 cm , so

Total displacement of tip = 2 × l = 2 × 5 cm = 10 cm

And

The min hand swap between 6 : 00 hour to 18 : 30 hour  = 12.5 hours

                                                                                              = 45000 sec

∵ velocity = $\dfrac{displacement}{time}$

                 = $\dfrac{l}{t}$

                 = $\dfrac{10}{45000}$

                = 2.2 × $10^{-4}$  cm/s

Hence, The average velocity of the tip is = 2.2 × $10^{-4}$  cm/s  Answer