A wall clock has a 5cm long minutes hand the average velocity of tip of the hand reaching 6 hrs to 18.30hrs
Answers
The example realeted of this question
Minute hand length =5cm
Average velocity =?
Time =6.00 am to 6.15 am
When the clock shows, 6.00 am , then the minute hand will point towards 12 and at 6.15 am then it shows at 90 degrees away from the before position.
Distance between initial and final position of tip of needle will be equal to displacement .
Displacement =hypotenese of right angle traingle.
Displacement =√5² +5²
=7.07cm=7.07/100=0.071m
Tota time= 15 mintues [from 6.am to 6.15am]
=15x60=900s
Average velocity= Total Displacement/total time
=0.071/900=7.88x10⁻⁵ m/s
∴ Average velocity of tip of the minute hand is 7.88x10⁻⁵ m
total displacement = 10cm
total time = 12 hours 30 minutes
= 45000 seconds
average velocity = 10cm / 45000
= 1/45 × 10^ -2 cms^-1
= 2.2×10^ -4 cms^-1
therefore, average velocity = 2.2×10^ -4 cms^ -1