A wall in a room has 1500 tiles.Each tile is in the shape of a parallelogram with base 16 cm and altitude 9 cm.Find the cost of cleaning the tiles at the rate of rupees 5 per square metre?
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From the question ,
it is given that the base of parallelogram b = 16
and
the altitude ,ie, height h = 9
area of parallelogram = b*h = 16*9 =144 sq.m
that means the above calculation is for one tile.
here we have 1500 tiles , so total area = 1500*144 = 21600 sq.m
cleaning cost per unit sq.m is 5
so total cleaning cost = 21600*5 = 1080000
it is given that the base of parallelogram b = 16
and
the altitude ,ie, height h = 9
area of parallelogram = b*h = 16*9 =144 sq.m
that means the above calculation is for one tile.
here we have 1500 tiles , so total area = 1500*144 = 21600 sq.m
cleaning cost per unit sq.m is 5
so total cleaning cost = 21600*5 = 1080000
ashfaqalimk:
sorry some mistake in above answer
From the question ,
it is given that the base of parallelogram b = 16cm =.16m
and
the altitude ,ie, height h = 9cm = .09m
area of parallelogram = b*h = .16*.09 =.0144 sq.m
that means the above calculation is for one tile.
here we have 1500 tiles , so total area = 1500*.0144 = 21.6 sq.m
cleaning cost per unit sq.m is 5
so total cleaning cost = 21.6*5 = 108
it is given that the base of parallelogram b = 16cm =.16m
and
the altitude ,ie, height h = 9cm = .09m
area of parallelogram = b*h = .16*.09 =.0144 sq.m
that means the above calculation is for one tile.
here we have 1500 tiles , so total area = 1500*.0144 = 21.6 sq.m
cleaning cost per unit sq.m is 5
so total cleaning cost = 21.6*5 = 108
total cost is Rs. 108/-
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