a wall is in the shape of trapezium the base of the wall is 7meter and top length is 5 meter the height of ball is 4 meter find the cost of plastering this work with cement at rate of rupees 140 m²
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First parallel side = 7m
Second parallel side = 5m
Height = 4m
> Area of trapezium = 1/2 × (a + b) × h
= 1/2 × ( 7 + 5 ) × 4
= 2 × 12
= 24m²
Rate of plastering = 140m²
> Total cost of plastering = ₹( 140 × 24 )
= ₹3,360
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Answer:
Answer: 3360 rupee
Step-by-step explanation:
Area of the wall = 1\2×(sum of all parallel sides)×height
= 1\2×(7m+5m)×4m
= 1\2×12m×4m
= 1\2×48m
= 24m^2
So,the cost of plastering = ₹140\m^2
= ₹3360
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