Math, asked by varhadisiddhesh8, 1 day ago

A wall is of the form of a trapezium with height 4 m and parallel sides being 3 m and 5 m. Find the cost of painting the wall if it has rate of painting as 25 per sq.m. ​

Answers

Answered by preeti353615
3

Answer:

A wall is of the form of a trapezium with a height 4 m and parallel sides being 3 m and 5 m. The cost of painting the wall if it has the rate of painting as 25 per sq.m is Rs 400.

Step-by-step explanation:

Given: The height of trapezium = 4 m,  

Two parallel sides length =3 m and 5 m.

Find the cost of painting the wall

Formula: Area of trapezium = 1/2 × (sum of parallel side)  × height

Area of wall = 1/2  × (5+3 )× 4

= 1/2 × 8 × 4

= 4 × 4

= 16 sq. m

The rate of painting is Rs. 25 per square meter.

The cost of painting for 16 sq. m is = 16 × 25= Rs. 400.

So, the cost of painting the wall is Rs 400.

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