Question

a wall length was to be built across an open ground th

Answer 1

is this a Pythagorean question? if so, the length of the wall can be calculated by getting a root of the total sum of distance of foot of the ladder from wall squared and the length of the ladder squared.


ie,


wall height =
$\sqrt{(ladder \: distance{}^{2} ) + (ladder \: length {}^{2} ) }$

Answer 2

l= 10m = 100cm
b=24m=2400cm
h=4m=400cm
volume of wall= lbh= 100*2400*400= 96000000cm cube

dimensions of brick= 24*10*8 cm
volue of each brick = 24*10*8 cm = 1920cm cube

let the no. of bricks be n
n*volume of each brick= volume of each wall
therefore, n= volume of the wall / volume of each brick
n=96000000 / 1920 cm cube
i.e.  n=50000
thus, no. of bricks required = 50000

hope it helps u