Math, asked by ojastaori, 1 year ago

A wall of a room is of dimensions 5 m × 4 m. It has a window of
dimensions 1.5 m × 1m and a door of dimensions 2.25 m × 1m.
Find the area of the wall which is to be painted.

Answers

Answered by qudsiya9950
50
Given,
dimension of wall = 5 m × 4 m
area = 20 sq.m
dimension of window = 1.5 m × 1 m
area = 1.5 sq.m
Dimension of door = 2.25 × 1 sq.m
area = 2.25 sq.m
area not to be paint = ( 1.5+2.25) sq.m = 3.75 sq.m
area to be painted = ( 20-3.75) sq.m
=> 16.25 sq .m
The area to be painted is 16.25 sq.m
Answered by RUDRAKSH19355
5

Step-by-step explanation:

Given, Length of the room =5m

Breadth of the room =4m

Area of the room =5×4=20m

2

Also,

Length of the window =1.5m and

Breadth of the window =1m

Area of the window =1.5×1=1.5m

2

Now,

Length of the door =2.25m

Breadth of the door =1m

Area of the door =2.25×1=2.25m

2

Now,

area of the wall to be painted = Area of the room - (Area of the window +Area of the door)

=20−(1.5+2.25)

=20−3.75

=16.25m

2

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