Question

A wall of length 10 m was to be built across an open ground. The height of the wall is 4 and thickness of the wall is 24 cm. If this wall is to be built up with bricks whose dimensions are 24 cm x 12 cm x 8 cm, how many bricks would be required?
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Answer 1

$\underline \mathbb{SOLUTION}$

$\bold\green{\underline{We\:know,}}$

》The volume of the wall and the sum of the volumes of the required number of brick is same.

》Length of the wall = 10× 100 cm

》Breath of the thickness of the wall = 24 cm

》Height of the wall = 4 × 100 = 400 cm

The wall is in the shape of a cuboid.

$= > volume = 1000 \times 24 \times 400 \: {cm}^{3}$

$\bold\green{\underline{Now,}}$

A brick is also a cuboid having length = 24 cm, breadth = 12 cm and height = 8 cm.

$volume \: of \: one \: brick = 24 \times 12 \times 8 {cm}^{3}$

$\bold\green{\underline{Required\:no\:of\:bricks}}$

$= > \frac{volume \: of \: wall}{volume \: of \: one \: brick}$

$\implies\: \frac{1000 \times 24 \times 400}{24 \times 12 \times 8}$

$\implies\:\frac{5000}{12}$

$\implies\: 4166.6$

$\boxed {BRICKS\:REQUIRED = 4166.6}$

_______________________________________

Answer 2

Answer:

Hey Mate , ......

For wall,

Total number of bricks = Volume of wall

$\frac{volume \: of \: wall?}{volume \: of \: bricks?}$

Length of Wall = 10m = 10 * 10 cm = 1000 cm

Breadth of wall = 24 cm

Height of wall = 4m = 4 * 10 cm = 400 cm

Volume of the wall = Length *Breadth * Height.

1000 * 24 * 400cm^2

For brick ,

Length of Brick = 24cm

Breadth of Brick = 12cm

Height of Brick = 8cm

Volume of each brick = Length * Breadth * Height

= 24 * 12 * 8

Now ,

Total number of bricks =

$\frac{volume \: of \: wall?}{volume \: of \: bricks?}$

$\frac{1000 \times 24 \times 400?}{24 \times 12 \times 8?}$

= 4166.6

= 4167 ( approx .).......

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