Question

A wall of length 10 m was to be built across an open ground. The height
of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built up with
bricks whose dimensions are 24 cm x 12 cm x 8 cm, how many bricks would be
required?​

Answer 1

Answer:

• 4167 Bricks are required to make the wall (approx.)

Explanation:

Given,

• Length of wall, L = 10 m
• Height of wall, H = 4 m
• Thickness of wall, B = 24 cm = 24/100 m = 0.24 m

• Dimensions of bricks are; 24 cm × 12 cm × 8 cm = 0.24 m × 0.12 m × 0.08 m

Since,

Volume of cuboid = Length × breadth × height

therefore,

→ Volume of Wall = 10 m × 4 m × 0.24 m

and,

→ Volume of each brick = 0.24 m × 0.12 m × 0.08 m

so,

→ Number of brick required = Volume of wall / Volume of each brick

→ No. of brick required = ( 10 m × 4 m × 0.24 m ) / ( 0.24 m × 0.12 m × 0.08 m )

→ No. of brick required = ( 10 m × 4 m ) / ( 0.12 m × 0.08 m )

→ No. of brick required = 4166.67 (Approx.)

That means,

• Number of brick required for making wall is 4167 (Approx.).

Answer 2

Step-by-step explanation:

${\huge{\underline{\boxed{\mathbb{question}}}}}$

A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built up with bricks whose dimensions are 24 cm x 12 cm x 8 cm, how many bricks would be required?

To find:

how many bricks would be required

Solution:

• formula used

volume = length×Breadth×Height

Length of wall = 10 m = 1000cm

Height of wall = 4 m = 400cm

Breadth or thickness of wall = 24 cm

volume = (1000×400×24)cm^3

Length of brick= 24 cm

Height of brick= 12 cm

Breadth of brick= 8 cm

volume = (24×12×8)cm^3

bricks required =

$\frac{1000 \times 400 \times 24}{24 \times 12 \times 8}$

$= > \frac{9,600,000}{2,304}$

$= 4,166.66667$

= 4167 approximately

Bricks required =4167 approximately

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