Question

A wall of length 10 m was to be built across an open ground. The height
of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built up with
bricks whose dimensions are 24 cm x 12 cm x 8 cm, how many bricks would be
required?
ill with all its bricks makes up the space occupied by it, we​

Answer 1

Answer:

$\large \star\underline {\underline\purple {\mathfrak {ᴀɴsᴡᴇʀ}}} \star$

$\{since \: the \: wall \: with \: all \: its \: bricks \: makes \: up \: the \: space \: occupied \: by \: it \\ we \: need \: to \: find \: the \: volme \: of \: the \: wall \: which \: is \: nothing \: nut \: a \: cuboid. \\ here, \: \: \: \\ length = \: 10 \: m \: = 1000cm \\ thickness = \: 24 \: \\ height = 4m = 400cm \\ therefore, \: \\ \: the \: volume \: of \: the \: wall = \: length \times thickness \times height \: = \: 1000 \times 24 \times 400 \: cm3 \\ now, \: each \: brick \: is \: a \: cuboid \: with \: length = 24 \: cm, \: breadth = 12cm \: and \: height = 8 \: cm \\ so, \: volume \: of \: each \: brick = \: Length×breadth×height \: \\ = 24 \times 12 \times 8 \: cm \\ so, \: number \: of \: bricks \: required = \frac{volume \: of \: the \: wll}{volume \: of \: each \: brick} \\ = \frac{1000 \times 24 \times 400}{24 \times 12 \times 8} \\ = 4166.6 \: (4167) \\ so, \: the \: wall \: requires \: 4167 \:$

$\large \star\underline {\underline\purple {\mathfrak {ʜᴏᴘᴇ \: ɪᴛ \: ʜᴇʟᴘs}}} \star$