Question

A wall of length 10 m was to be built across an open ground. The height
of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built
hicks whose dimensions are 24 cm * 12 cm x 8 cm, how many bricks would be
up
with
required?
​

Answer 1

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To find the number of bricks:-

$\frac{volume \: of \: wall}{volume \: of \: brick} = \frac{10 \times 0.24 \times 4}{0.24 \times 0.12 \times 0.8}$

$= > \frac{9.6}{0.0234 } =416.66$

417 bricks are needed.

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Answer 2

GivEn:

Dimensions of wall,

• Length of wall, l = 10 m = 100 cm

• Breadth of wall, b = 42 m = 4200 cm

• Height of wall, h = 5 m = 500 cm

Dimensions of one brick,

• Length of brick, l = 42 cm

• Breadth of brick, b = 12 cm

• Height of brick, h = 10 cm

To find:

• No. of bricks?

Solution:

We know that,

☯ Both wall and bricks are in cuboidal shape.

★ Volume of cuboid = l × b × h

Therefore,

Volume of wall = 100 cm × 4200 cm × 500 cm

⇏ 21000000 cm³

Also,

Volume of each brick = 42 cm × 12cm × 10 cm

⇏ 5040 cm³

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Let the number of bricks required be n.

No. of bricks = Volume of walls/Volume of 1 brick

⇏ n= 21000000/5040

⇏ n = 4166.67

Since, The brick is to be taken as a whole.

∴ No. of brick required in a walls is 4167.