Question

A wall of length 10m was to built
across an open ground. The height of the wall is 4cm and thickness of the wall is 24cm. if this wall is to be built up with bricks whose dimensions are 24×12cm×8cm, how many bricks would be required?​

Answer 1

Step-by-step explanation:

length of wall(l)=10m=1000cm

height of wall(h)=4cm

breadth of wall(b)=24cm

Volume of wall=l×b×h

=1000×24×4

=96000cm³

length of brick(l)=24cm

breadth of brick(b)=12cm

height of brick(h)=8cm

Volume of the brick=l×b×h

=24×12×8

=2304cm³

No. of bricks required to construct the wall

=Volume of wall/Volume of brick

=96000/2304

=41.67

≈42 bricks

Answer 2

Solution :-

since the wall with all its bricks makes up the space occupied by it we need to find the volume of the wall which is nothing but a cuboid.

• Length (l) = 10m = 1000cm
• Thickness (t) = 24 cm
• Height (h) = 4 m = 400 cm

Volume of the wall

⠀⠀⠀⠀⠀⠀⠀⠀ = L × T × H

⠀⠀⠀⠀⠀⠀⠀⠀= 1000 × 24 × 400 ${cm}^{3}$

Now, each brick is a cuboid

• Length = 24 cm
• Breadth = 12cm
• Height = 8 cm

Volume

⠀⠀⠀⠀⠀⠀⠀⠀= Length × breadth × height

⠀⠀⠀⠀⠀⠀⠀⠀= 24× 12 × 8 ${cm}^{3}$

so , no. of brick's required

⠀⠀⠀⠀⠀⠀= $\dfrac{volume\:of\:the\:wall}{volume\:of\:each\:brick}$

⠀⠀⠀⠀⠀⠀= $\dfrac{1000×24×400}{24×12×8}$

⠀⠀⠀⠀⠀⠀= 4166.6

So , the wall requires 4167 bricks