A warehouse is used as a granary. It is in the shape of a cuboid surmounted by half-cylinder. The base of ware house is 6m x 14m and its height is 8m. Find the surface area of the non cuboidal part of the ware house.
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2
Height of the cylinder will become the length of the cylinder
so, h = 14m
diametre the cylinder will become the breadth of the cubiod
so, r = 3m
surface area of non cubiodal part = curved surface area of cylinder divied by 2
so ,
= 22/7 * 3 * 14
= 132 m2
so, h = 14m
diametre the cylinder will become the breadth of the cubiod
so, r = 3m
surface area of non cubiodal part = curved surface area of cylinder divied by 2
so ,
= 22/7 * 3 * 14
= 132 m2
Answered by
1
Dimensions of cuboid are 6*14*8 m
∴ height of cylinder = 14 m
and radius of base = 6/2 m = 3m
Now, SA of non- cuboidal part = CSA of cylinder/2
= 2πrh/2
= πrh
= 22/7 * 3 * 2
=132 m²
∴ height of cylinder = 14 m
and radius of base = 6/2 m = 3m
Now, SA of non- cuboidal part = CSA of cylinder/2
= 2πrh/2
= πrh
= 22/7 * 3 * 2
=132 m²
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