Question

A washbasin has an exit pipe covered with a plug of area 12 cm2 . A chain is attached to the centre of the plug to assist in pulling the plug away from the exit hole. The washbasin contains water to a depth of 0.080 m. The density of the water is 1000 kg /m3 What is the force acting on the plug due to the water? A= 0.96N B= 800N C =9600N D= 80 000N

Answer 1

Answer:

A=0.96N

Explanation:

Formula: Pressure = density x gravitational field x height.

Pressure = 1000kg/m^3  x 10N/kg x 0.08m = 800 Pa

Convert cm^2 to m^2 because area's symbol unit of m^2

Formula: divide by 10000

12cm^2 = 0.0012m^2

Formula: Pressure = Force/ Area

800Pa = Force/ 0.0012m^2

Force= 800 x 0.0012m^2 = 0.96N

Answer 2

Answer:A=0.96N

Explanation:

Formula: Pressure = density x gravitational field x height.