A watch which gains 5 seconds in 3 minutes was set right at 7
a.M. In the afternoon of the same day, when the watch indicated quarter past 4 o'clock, the true time is:
a. 59 7 min. Past 3 12
b. 4 p.M.
c. 58 7 min. Past 3 11
d. 2 3 min. Past 4 11
Answers
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Watch gains 5 seconds in 3 minutes or 5 seconds in every 180 seconds.
Time passed in correct clock = 180 seconds
Time passed in faulty clock = 185 seconds.
Given: Time passed in faulty clock = 9 hours and 15 minutes = 9*60*60 + 15*60 = 33300 seconds
Time elapsed in the correct clock = 180/185*33300 = 32400 seconds = 9 hours.
Hence the time in correct clock = 7 + 9 hours = 4 PM Option B
Alternative solution.
Clock gains 5 seconds every 3 minutes = 100 seconds every hour (60 minutes) = 900 seconds every 9 hours = 15 minutes every 9 hours.
Hence when the faulty clock shows 4:15 PM, the actual clock should show 15 minutes less i.e. 4:00 PM
B. 4 PM is the correct answer.
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