Question

A watch which gains uniformly was observed to be 1 minute slow at 8 : 00 a.m. On a day at 6 : 00 p.m. on the same day it was 1 minute fast. At what time did the which show the correct time ?

Answer 1

Answer:

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Answer 2

Given:

• Watch was 1 minute slow at 8.00 am on a day
• Watch was 1 minute fast at 6.00 pm on same day.

To find:

• Time at which watch showed correct time

Solution:

• Total time gained by clock = 1 minute + 1 minute = 2 minutes.
• Total time required to gain 2 minutes = 10 hours.
• Hence watch gains 2 minutes in (10*60) minutes = 600 minutes.
• Avg gain per minute = 2/600 = 1/300
• For watch to show correct time, it has to gain 1 minute after 8 am.
• Let time required to gain 1 minute be x.
• ∴ x * (1/300) = 1.
• ∴ x = 300 minutes.
• Hence, watch shows correct time after 300 minutes i.e 5 hours after 8 a.m

Answer:

Watch shows correct time at 1 p.m.