Math, asked by sbatturi432, 2 months ago

. A watch, which gains uniformly was
observed to be 6 minutes slow at 9:00 a.m.
on a Tuesday and 3 minutes fast at 12:00
noon on the subsequent Wednesday.
When did the watch show the correct time?
(A) 9:00 p.m. on Tuesday
(B) 12:00 a.m. on Wednesday
(C) 3:00 a.m. on Wednesday
(D) 6:00 a.m. on Wednesday​

Answers

Answered by tpalak105
4

Answer:

11:00am

Step-by-step explanation:

Duration from 9:00 am to 12 noon

Duration= 3hours = 180mins

find the extra minutes moved in that 3 hours

Extra mins moved= 3+6= 9mins

The clock moved 9 mins extra in that 3 hours

3hours = 9 mins extra

1 hour = 3 mins extra

so we add extra 3mins after every hour

9:00 am= showing 8.54am

10:00am= showing 9.57am

11:00am= showing 11:00am

12:00pm= showing 12.03 pm

The time is correct at 11:00am

I hope it will help you

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