Physics, asked by 20100096110010, 1 month ago

A water boiler has a resistance of 88 Ω.How much current is drawn when a voltage of 220 V is applied to it?​

Answers

Answered by nirman95
4

Given:

A water boiler has a resistance of 88 Ω.

To find:

Current drawn when attached to a voltage of 220 Volts ?

Calculation:

In this kind of questions, you can use OHM'S LAW:

  • OHM'S Law states that the potential difference is directly proportional to the current in a circuit at constant ambient temperature.

 \rm\therefore \: i =  \dfrac{V}{R}

 \rm  \implies\: i =  \dfrac{220}{88}

 \rm  \implies\: i = 2.5 \: ampere

So , current drawn is 2.5 Amperes.

Answered by ayushsingh033
0

Explanation:

Given: R = 88 ohm & V = 220 V

To Find: Current (I) = ?

We know that,

=> I = V/R

=> I = 220/88

=> I = 2.5

.°. I = 2.5 A

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