A water cooler cools at the rate of 5degree celcius per hour. The temperature of water at A certain time is 25degree celcius.Find what will be it's temperature after 8 hours
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Answer:
initial temperature = 40°C
Rate of change in temperature = 5°C/hour
time = 10 hours
So, in 10 hours the temp would be decreased
by 10×5=50°C
So, final temperature = 40−50° =−10°C
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