Question

A water drop of diameter 2mm is split up into 10⁹ identical water drops. Calculate the work done in this process. The surface tension of water is 7.3 x10² Nm-¹). ​

Answer 1

Answer:

Solution:

Let a water drop of radius R be split up into 10^9 identical water drops each of radius r.

R = D/2 = 2/2 = 1 mm= 1 × 10-3 m

No. droplets n = 109 ; T = 7.3 × 10-2 N/m

W = 4 π R2 T [n1/3 -1]

= 4π (10-3 )2 × 7.3 × 10-2 [(109 )1/3 -1]

=9.17 × 10-4 J

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Answer 2

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Let a water drop of radius R be split up into 10⁹ identical water drops of each radius r.

R = D/2

R = 2/2

R = 1m

R = 1 × 10-³

No. of water droplet = 109

T = 7.3 × 10-² Nm

W= 4πR²T [ n1 / 3-1]

W = 4 × 10-³ × 7.3 × 10-² [ 109/3-1]

W = 9.17 × 10-⁴