Question

A water drop of volume 2×10^-3 m^3 falls from a height of 100m. Then work done by gravitational force on it is

Answer 1

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here is your answer

Answer 2

Given :

Volume of water droplet , $V=2\times 10^{-3}\ m^3$ .

Height from which it falls , h = 100 m .

To Find :

Work done by gravitational force on droplet .

Solution :

We know , density of water is $1\ kg/m^3$ .

So , mass of water droplet is equal to magnitude of its volume .

Therefore , $m=2\times 10^{-3}\ kg$ .

Now , potential energy is given by :

$P=mgh\\\\P=2\times 10^{-3}\times 9.8\times 100\ J\\\\P=1.96\ J$

Therefore , work done by gravitational force on droplet is 1.96 J .

Learn More :

Gravitational potential

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