Question

A water drop of volume 2 x 10 ek the power of minus 8 metre per second falls
from a height of 100 m. Then work done by the
gravitational force on it is​

Answer 1

Volume of water droplet ,

V=2\times 10^{-3}\ m^3

Height from which it falls , h = 100 m .

To Find :

Work done by gravitational force on droplet .

Solution :

We know , density of water is

So , mass of water droplet is equal to magnitude of its volume .

1\ kg/m^3

Therefore ,

m=2\times 10^{-3}\ kg

Now , potential energy is given by :

\begin{gathered}P=mgh\\\\P=2\times 10^{-3}\times 9.8\times 100\ J\\\\P=1.96\ J\end{gathered}

Therefore , work done by gravitational force on droplet is 1.96 J .

Learn More :

Gravitational potential

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