Question

a Water drops fall from rest from a nozzle from a height of 5m at regular interval of time such that the first drop reaches the ground when sixth drop is released from the nozzle. The height of the fourth drop froom the ground is (g = 10 ms-2)

a) 3.2 m
b) 0.8 m
c) 1.8 m
d) 4.2 m​

Answer 1

Answer:

Solution

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Correct option is C)

Height of tap = 5m and (g) = 10m/sec

2

For the first drop, 5=ut+gt

2

=(0×t)+×10t

2v

=5t

2

or t

2

=1 or t=1.

It mean that the third drop leaves after one second of the first drop. Or, each drop leaves after every 0.5 sec.

Distance covered by the second drop in 0.5 sec.

=(0.5)

2

=1.25m

Therefore, distance of the second drop above the ground

=5−1.25=3.75m.

E