Question

. A water filled cylinder of height 50 cm and base area 20 cm is placed on a table with
the base on the table. The thrust offered by water on the table is​

Answer 1

The thrust offered by water on the table is 9.8 N.

• Given,

Height (h) of the cylinder = 50 cm

Area (a) of the base of the cylinder = 20 cm²

• Thrust offered by water means force exerted by water on the table.

Force = Pressure × Area

• Pressure exerted by water on table = height of the cylinder (h) × density of water (d) × acceleration due to gravity (g)

Density of water = 1 g/cm³

Acceleration due to gravity =

980 cm/s²

Pressure = 50 cm × 1 g/cm³ × 980 cm/s² = 49000 g/cm/s² = 49 × 10³ g/cm/s²

• Now, thrust (F) offered by water on the table = P × A

F = 49 × 10³ g/cm/s² × 20 cm²

=> F = 980 × 10³ g/cm/s²

=> F = 9.8 × 10² × 10³ dynes ( 1 g/cm/s = 1 dyne) = 9.8 × 10^5 dynes

=> F = 9.8 N ( 10^5 dynes = 1 N)

• Thus, the thrust offered by water on the table is 9.8 N.

Answer 2

The answer is 10N

step by step explanation is provided in the image above