Question

A water heater is connected to a 230V supply and there is a current of 26A in the heater. It takes 20 minutes to heat the water to the required temperature. How much energy is supplied by the heater? A 6.0 × 103 J B 1.0 × 104 J C 1.2 × 105 J D 7.2 × 106 J

Answer 1

Answer:

energy is supplied by the heater is 7176 kJ so it approximately equal to option 4

Explanation:

for explanation see the attached photo

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Answer 2

Answer:

The correct option is D. (7.2 x $10^6$ J).

Explanation:

From the above question,

They have given :

We can use the components for electrical strength to calculate the power provided by means of the heater:

                  Energy = Power x Time

Where strength is the electrical energy in watts and time is the period of use in seconds.

First, we want to calculate the energy of the heater the use of Ohm's law:

                    V = IR

where,

         V is the voltage, I is the current, and R is the resistance.

Rearranging the equation, we get:

                     R = V / I

                     R = 230V / 26A

                     R= 8.846Ω

Now we can calculate the energy of the heater the usage of the formula:

P = IV = $I^2$R = (26A)$.^{2}$ x 8.846Ω

                    = 6,779.88W

(Note: We used the 2d shape of the system due to the fact we understand the cutting-edge and resistance.)

Next, we want to convert the length of use from minutes to seconds:

                      Time = 20 minutes x 60 seconds/minute

                      Time = 1200 seconds

Finally, we can calculate the power furnished by using the heater the use of the formula:

              Energy = Power x Time

              Energy = 6,779.88W x 1200s

              Energy = 8,135,856J

Therefore, the strength provided by means of the heater is 8.1 x $10^6$ J.

The correct option is D. (7.2 x $10^6$ J).

For more such related questions : https://brainly.in/question/5749639

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