A water insoluble substance 'X' on reacting with dilute sulphuric acid released a colorless and odorless gas accompanied by brisk effervescence. When the gas was passed through lime water, the solution turned blue litmus to red. On bubbling the gas through lime water, it initially became milky and the milkness disappeared when the gas was passed in excess. Identify the substance X and write the chemical equation. Is this answer correct: NaCO3+ H2SO4 --- NA2SO4 + H20 + CO2
Answers
Answered by
41
Sodium carbonate on heating with sulphuric acid we get sodium sulphate , CO2 and water
Na2CO3 +H2SO4 ---->Na2SO4 +CO2 +H2O
ON PASSING CO2 gas to lime water it turns milky white due to formation of CaCO3.
Ca(OH)2 +CO2 ---->CaCO3 +H2O
IF EXCESS OF CO2 IS PASSED, the milky white colour disappers due to formation of calciumhydrogen carbonate.
CaCO3+CO2+H2O---->Ca(HCO3)2
Hence Substance X is SodiumCarbonate.
Na2CO3 +H2SO4 ---->Na2SO4 +CO2 +H2O
ON PASSING CO2 gas to lime water it turns milky white due to formation of CaCO3.
Ca(OH)2 +CO2 ---->CaCO3 +H2O
IF EXCESS OF CO2 IS PASSED, the milky white colour disappers due to formation of calciumhydrogen carbonate.
CaCO3+CO2+H2O---->Ca(HCO3)2
Hence Substance X is SodiumCarbonate.
Answered by
6
Explanation:
the substance X is sodium carbonate
Similar questions
English,
8 months ago
Computer Science,
8 months ago
Environmental Sciences,
1 year ago
Science,
1 year ago
Social Sciences,
1 year ago