Question

a water on 12 percent loss sold at rs 550 find the cost price of water
​

Answer 1

Answer:

Given:

S.P= ₹ 540, loss%=5%

Let the Cost price = C.P

Loss% =( loss/C.P) × 100

Loss% =( (CP- SP)/CP ) × 100

5 =( (CP - 540)/CP ) × 100

5/100 = ( (CP - 540)/CP )  

1/20 = ( (CP - 540)/CP )  

CP = 20 (CP - 540)

20 = 20CP - 10800

20CP - CP = 10800

19CP = 10800

CP = 10800/19

CP =₹ 568.42

Hence, the cost price of an item = ₹ 568.42

Answer 2

Answer:

let the cost price be x

therefore

loss= loss% of cost price

=12%of x

=12x/100

therefore

cost price = Selling price-profit

x=550-12x/100

100x=55000-12x

112x=55000

x=Rs. 491.071

Hope it helps