Question

A water pond appears to be 3.6m deep. If the refractive index ofwater is 4/3, the actual depth of the pond is-​

Answer 1

Explanation:

Apparent depth = 2.7 m

w=4/3

actual depth=apparent depth×w

=2.7×4/3

=3.6m

Answer 2

Given:

The depth of pond = $3.6$ m

The refractive index of water = $\frac{4}{3}$

To find:

The actual depth of the pond

Formula:

$Refractive\;index\;=\;\frac{Real\;depth}{Apparent\;depth}$

Explanation:

$Refractive\;index\;=\;\frac{Real\;depth}{Apparent\;depth}$

$Real\;depth\;=\;Refractive\;index\;\times\;Apparent\;depth$

$Real\;depth\;=\;\frac43\;\times\;3.6$

Real depth = $4.8$ m

Answer:

Therefore, the actual depth of the pond is $4.8$ m