Question

A water pump can lift 1000 Kg of water to a height of 4 m in 300 sec.

Find power of the pump. Given g=10m/sec2

(Hint: Here force (f) is

weight of water, f=1000x10 N, h=4m and t=300sec)

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Answer 1

Answer:

Given,

m=1000kg

t=1min=60sec

h=10m

v=10m/s

g=10m/s2

Power, P=tmgh+21mv2

P=601000×10×10+21×1000×10×10

P=60100000+50000=60150000=2500W

As we know that, 1horse−power=746Watt

1W=7461horse−power

2500W=7462500=3.25HP