Physics, asked by theswastik7, 8 months ago

a water pump driven by petrol raises water at the rate of 0.5 metre cube per minute from a depth of 30 metre if the pump is 70% efficient What power is developed by the engine ​

Answers

Answered by 05dhruvkumar1980
1

Answer:

This discussion on A water pump driven by petrol rises water at a rate of 0.5 m3 min–1 from a depth of 30 m. If the pump is 70% efficient, what power is developed by the engine? Answer=1715W? is done on EduRev Study Group by NEET Students.

Answered by sudhirgupta001
3

Explanation:

Volume = 0.5 m^3

Density of water = 1000 kg/m^3

Height = 30 m

Gravity = 9.8 m/s^2

Work done = potential energy = mass × gravity × height

Density = mass / volume

Mass = density × volume

Therefore ,

Work = Volume × Density × gravity × height

= 0.5 × 1000 × 9.8 × 30

= 147000 Joules

Power = Work / Time

= 147000 J/ 1 min = 147000 J/ 60 sec = 2450 Watt

Let the real power be x .

 \frac{70}{100}x = 2450

x = 3500 \: watt

Therefore , the power of the pump is 3500 Watt.

I hope it helps you. If you have any doubts, then don't hesitate to ask.

Similar questions