Question

A water pump is used to lift 50 kg of water through a height of 50 m in 5 s. Taking g = 10 N kg-1, calculate the power rating of the pump if it is 50% efficient...​

Answer 1

Answer:

ANSWER

Force=m×g

F=500×10=5000N

Work=F×s

W=5000×80=4×10

5

joule.

Power=work/time

P=4×10

5

/10=4×10

4

=40kW.

Power Rating=Useful power/ efficiency

Power Rating = 40k/0.4=100kW

Answer 2

Height = 25m

Time = 5s

Volume = 50l

${ \pink{ \bf{ Let's \: convert \: volume \:to \:density: }}}$

density = mass / volume

So,

${ \pink{ \bf{ 1m² = 1000l }}}$

${ \pink{ \bf{ density = mass / volume }}}$

1000=mass/(1/1000×50)

mass=1000×50×1/1000

${ \pink{ \bf{ =50kg }}}$

${ \pink{ \bf{W=F=mg=50×10=500 }}}$

P=500×25/5

${ \pink{ \bf{P=2500W \: Ans }}}$