Physics, asked by deependra1357, 1 year ago

A water pump raises 50 kg of water through a height of 25m in 5 second.calculate the power which the pump supplies.(take g=10m/s)

Answers

Answered by RohJain
9
you can solve it by using potential energy formula for power
power = mgh / time
50 * 10 * 25 / 5
this turns out to be 2500 watt or 2.5 kw
Answered by Brenquoler
22

Height = 25m

Time = 5s

Volume = 50l

 { \orange{ \bf{  Let's \: convert \: volume \:to \:density: }}}

density = mass / volume

So,

 { \orange{ \bf{  1m² = 1000l }}}

 { \orange{ \bf{ density = mass / volume  }}}

1000=mass/(1/1000×50)

mass=1000×50×1/1000

 { \orange{ \bf{  =50kg }}}

 { \orange{ \bf{W=F=mg=50×10=500   }}}

P=500×25/5

 { \orange{ \bf{P=2500W \: Ans   }}}

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