Physics, asked by zeeshanali1, 1 year ago

a water pump raises 50 litres of water through a height of 25 m in 5 s calculate the power which the pumps supplies take g 10newton per kg and density of water 1000 kg per meter cube

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Answers

Answered by abhi178

422

mass=volume*density
=(50litres)(1000kg/m^3)
=(50/1000m^3)(1000kg/m^3)
=50kg
use, energy=mgh=50kg (10N/kg)(25m)
=12500Nm=12500j
power=energy/time
= 12500j/5sec
=2500j/sec

abhi178: you know mass=volume multiply into density in this way we find mass because according to formula of energy mass is require

abhi178: I think you don't how to change litre to m^3

abhi178: actually one litre equal 1/1000 m^3

abhi178: know I hope you understand

zeeshanali1: thank you very much

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Answered by kingofself

146

The pump supply needs power about 2500 watts.

Given:

Volume of water = 50 litres

Height of the water raised by the pump = 25 m

Time taken to raise the water through the pump = 5 seconds

To find:

Power needed to pump to supply 10N/kg.

Solution:

Mass = volume x density

$=50 \text { liters } \mathrm{x} 1000 \mathrm{kg} / \mathrm{m}^{3}$

$=\frac{50}{1000} \times 1000$

Mass = 50 kg

Energy = m X g X h

$=50 \times 10 \times 25$

= 12500 joule

Energy = work done

Power $=\frac{\text {work done}}{\text {time}}$

$=\frac{12500}{5}$

Power = 2500 watts

2500 watt is required to operate the water pump of given condition.

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