A water pumps lifts 18*10³ litre of water to a height of 30 m in one hour. If the efficiency of pump is 75% of power of pump is [ g = 10 m/s²]
joyashrib:
Answer is 200w
Convert one hour into second and 75%into 0.75
Equate as 0.75 *p *3600=18000*30
No m wrong because you gave half the info
Volume of water is given not mass
Ya that is the point I know I have given wrong answer
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There is a calculation to find the power consumption of a water pump. A typical water pump's wattage can vary between 250 watts to 1,100 watts. Take the wattage of the specific water pump and multiply it times how many hours a day it runs. Then, multiply it by how many days a year it runs, and divide by 1000.
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Volume =18*10^3 l
Density =mass/volume
Mass=18*10^6kg
P=W\t
P=mgh/t
P=18*10^6*10*30/60*60
P=1.5MW
If efficiency =75%
P=75/100*1.5*10^6
P=1125*10^3
P=1125KW
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